Base | Representation |
---|---|
bin | 1011100110011101… |
… | …1110001111100011 |
3 | 22001000210022121221 |
4 | 2321213132033203 |
5 | 22334204214301 |
6 | 1233002355511 |
7 | 140112455233 |
oct | 27147361743 |
9 | 8030708557 |
10 | 3114132451 |
11 | 1358934891 |
12 | 72aabbb97 |
13 | 3a8235831 |
14 | 217835cc3 |
15 | 1335dada1 |
hex | b99de3e3 |
3114132451 has 2 divisors, whose sum is σ = 3114132452. Its totient is φ = 3114132450.
The previous prime is 3114132419. The next prime is 3114132473. The reversal of 3114132451 is 1542314113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3114132451 - 25 = 3114132419 is a prime.
It is not a weakly prime, because it can be changed into another prime (3114132401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557066225 + 1557066226.
It is an arithmetic number, because the mean of its divisors is an integer number (1557066226).
Almost surely, 23114132451 is an apocalyptic number.
3114132451 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114132451 is an equidigital number, since it uses as much as digits as its factorization.
3114132451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 25.
The square root of 3114132451 is about 55804.4124689079. The cubic root of 3114132451 is about 1460.3121323952.
Adding to 3114132451 its reverse (1542314113), we get a palindrome (4656446564).
The spelling of 3114132451 in words is "three billion, one hundred fourteen million, one hundred thirty-two thousand, four hundred fifty-one".
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