Base | Representation |
---|---|
bin | 11101000000001011… |
… | …010011101101001001 |
3 | 2222101022011221201012 |
4 | 131000023103231021 |
5 | 1002234204232233 |
6 | 22150045533305 |
7 | 2151500121461 |
oct | 350013235511 |
9 | 88338157635 |
10 | 31141477193 |
11 | 12230608812 |
12 | 6051274235 |
13 | 2c23a08aa8 |
14 | 1715ca2ba1 |
15 | c23e54548 |
hex | 7402d3b49 |
31141477193 has 2 divisors, whose sum is σ = 31141477194. Its totient is φ = 31141477192.
The previous prime is 31141477139. The next prime is 31141477231. The reversal of 31141477193 is 39177414113.
Together with previous prime (31141477139) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16380928144 + 14760549049 = 127988^2 + 121493^2 .
It is a cyclic number.
It is not a de Polignac number, because 31141477193 - 210 = 31141476169 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31141477193.
It is not a weakly prime, because it can be changed into another prime (31141473193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15570738596 + 15570738597.
It is an arithmetic number, because the mean of its divisors is an integer number (15570738597).
Almost surely, 231141477193 is an apocalyptic number.
It is an amenable number.
31141477193 is a deficient number, since it is larger than the sum of its proper divisors (1).
31141477193 is an equidigital number, since it uses as much as digits as its factorization.
31141477193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 63504, while the sum is 41.
The spelling of 31141477193 in words is "thirty-one billion, one hundred forty-one million, four hundred seventy-seven thousand, one hundred ninety-three".
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