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31142000401 = 253912265459
BaseRepresentation
bin11101000000001101…
…010011011100010001
32222101100011112102021
4131000031103130101
51002234323003101
622150105051441
72151504431041
oct350015233421
988340145367
1031142000401
1112230935916
126051486b81
132c23b5cc95
141715d9b721
15c240095a1
hex740353711

31142000401 has 4 divisors (see below), whose sum is σ = 31154268400. Its totient is φ = 31129732404.

The previous prime is 31142000387. The next prime is 31142000473. The reversal of 31142000401 is 10400024113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31142000401 - 211 = 31141998353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31142000101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6130191 + ... + 6135268.

It is an arithmetic number, because the mean of its divisors is an integer number (7788567100).

Almost surely, 231142000401 is an apocalyptic number.

It is an amenable number.

31142000401 is a deficient number, since it is larger than the sum of its proper divisors (12267999).

31142000401 is a wasteful number, since it uses less digits than its factorization.

31142000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12267998.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 31142000401 its reverse (10400024113), we get a palindrome (41542024514).

The spelling of 31142000401 in words is "thirty-one billion, one hundred forty-two million, four hundred one", and thus it is an aban number.

Divisors: 1 2539 12265459 31142000401