Base | Representation |
---|---|
bin | 100011011001111100111001… |
… | …1010011100001110111010011 |
3 | 1111211200102022002011201120211 |
4 | 1012303321303103201313103 |
5 | 311304432131330212433 |
6 | 3022204550053344551 |
7 | 122412035022166615 |
oct | 10663716323416723 |
9 | 1454612262151524 |
10 | 311430013132243 |
11 | 9025a7aa4a4255 |
12 | 2ab19281338157 |
13 | 104a0955179745 |
14 | 56c9416236db5 |
15 | 26010217818cd |
hex | 11b3e734e1dd3 |
311430013132243 has 2 divisors, whose sum is σ = 311430013132244. Its totient is φ = 311430013132242.
The previous prime is 311430013132229. The next prime is 311430013132279. The reversal of 311430013132243 is 342231310034113.
It is a weak prime.
It is an emirp because it is prime and its reverse (342231310034113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311430013132243 - 229 = 311429476261331 is a prime.
It is a super-2 number, since 2×3114300131322432 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311430013532243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715006566121 + 155715006566122.
It is an arithmetic number, because the mean of its divisors is an integer number (155715006566122).
Almost surely, 2311430013132243 is an apocalyptic number.
311430013132243 is a deficient number, since it is larger than the sum of its proper divisors (1).
311430013132243 is an equidigital number, since it uses as much as digits as its factorization.
311430013132243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 311430013132243 its reverse (342231310034113), we get a palindrome (653661323166356).
The spelling of 311430013132243 in words is "three hundred eleven trillion, four hundred thirty billion, thirteen million, one hundred thirty-two thousand, two hundred forty-three".
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