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311430034412242 = 2255161040775071
BaseRepresentation
bin100011011001111100111010…
…0100100101101001011010010
31111211200102100120012212020221
41012303321310210231023102
5311304432202302142432
63022204552133423254
7122412035401106464
oct10663716444551322
91454612316185227
10311430034412242
119025a810509229
122ab1928849ab2a
13104a09596ba665
1456c9418db6134
152601023586b97
hex11b3e7492d2d2

311430034412242 has 8 divisors (see below), whose sum is σ = 467328173951232. Its totient is φ = 155653976428500.

The previous prime is 311430034412221. The next prime is 311430034412257. The reversal of 311430034412242 is 242214430034113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 311430034412198 and 311430034412207.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30520382434 + ... + 30520392637.

It is an arithmetic number, because the mean of its divisors is an integer number (58416021743904).

Almost surely, 2311430034412242 is an apocalyptic number.

311430034412242 is a deficient number, since it is larger than the sum of its proper divisors (155898139538990).

311430034412242 is a wasteful number, since it uses less digits than its factorization.

311430034412242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61040777624.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 311430034412242 its reverse (242214430034113), we get a palindrome (553644464446355).

The spelling of 311430034412242 in words is "three hundred eleven trillion, four hundred thirty billion, thirty-four million, four hundred twelve thousand, two hundred forty-two".

Divisors: 1 2 2551 5102 61040775071 122081550142 155715017206121 311430034412242