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311430314222242 = 2155715157111121
BaseRepresentation
bin100011011001111101000010…
…1010000000110001010100010
31111211200110002001201200102021
41012303322011100012022202
5311304433240420102432
63022205040011012054
7122412045336336205
oct10663720520061242
91454613061650367
10311430314222242
119025a944452666
122ab1934613a02a
13104a09a26696c7
1456c944421193c
15260103ce08697
hex11b3e854062a2

311430314222242 has 4 divisors (see below), whose sum is σ = 467145471333366. Its totient is φ = 155715157111120.

The previous prime is 311430314222231. The next prime is 311430314222411. The reversal of 311430314222242 is 242222413034113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 206736919965801 + 104693394256441 = 14378349^2 + 10231979^2 .

It is a junction number, because it is equal to n+sod(n) for n = 311430314222198 and 311430314222207.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77857578555559 + ... + 77857578555562.

Almost surely, 2311430314222242 is an apocalyptic number.

311430314222242 is a deficient number, since it is larger than the sum of its proper divisors (155715157111124).

311430314222242 is a wasteful number, since it uses less digits than its factorization.

311430314222242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155715157111123.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 311430314222242 its reverse (242222413034113), we get a palindrome (553652727256355).

The spelling of 311430314222242 in words is "three hundred eleven trillion, four hundred thirty billion, three hundred fourteen million, two hundred twenty-two thousand, two hundred forty-two".

Divisors: 1 2 155715157111121 311430314222242