3114310134113 has 4 divisors (see below), whose sum is σ = 3114449542848. Its totient is φ = 3114170725380.

The previous prime is 3114310134077. The next prime is 3114310134127.

3114310134113 is nontrivially palindromic in base 10.

3114310134113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3114310134113 - 2¹⁰ = 3114310133089 is a prime.

It is a super-2 number, since 2×3114310134113² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3114310154113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69670853 + ... + 69715538.

It is an arithmetic number, because the mean of its divisors is an integer number (778612385712).

Almost surely, 2^{3114310134113} is an apocalyptic number.

It is an amenable number.

3114310134113 is a deficient number, since it is larger than the sum of its proper divisors (139408735).

3114310134113 is a wasteful number, since it uses less digits than its factorization.

3114310134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139408734.

The product of its (nonzero) digits is 1296, while the sum is 26.

It can be divided in two parts, 3114310 and 134113, that added together give a palindrome (3248423).

The spelling of 3114310134113 in words is "three trillion, one hundred fourteen billion, three hundred ten million, one hundred thirty-four thousand, one hundred thirteen".