311431340402331 has 8 divisors (see below), whose sum is σ = 415241997525264. Its totient is φ = 207620788440480.

The previous prime is 311431340402267. The next prime is 311431340402363. The reversal of 311431340402331 is 133204043134113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 311431340402331 - 2⁶ = 311431340402267 is a prime.

It is a super-2 number, since 2×311431340402331² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311431340402292 and 311431340402301.

It is not an unprimeable number, because it can be changed into a prime (311431340402381) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19099180 + ... + 31426761.

It is an arithmetic number, because the mean of its divisors is an integer number (51905249690658).

Almost surely, 2^{311431340402331} is an apocalyptic number.

311431340402331 is a deficient number, since it is larger than the sum of its proper divisors (103810657122933).

311431340402331 is a wasteful number, since it uses less digits than its factorization.

311431340402331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52580541.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 311431340402331 its reverse (133204043134113), we get a palindrome (444635383536444).

The spelling of 311431340402331 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred forty million, four hundred two thousand, three hundred thirty-one".