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311434666434113 = 1512062481234663
BaseRepresentation
bin100011011001111111000100…
…0101010011101111001000001
31111211200212022101011221201112
41012303332020222131321001
5311310021144101342423
63022211035522013105
7122412261234461435
oct10663761052357101
91454625271157645
10311434666434113
1190261778131882
122ab1a15b7a7195
13104a1217239cc1
1456c973824a9c5
1526011e5052a78
hex11b3f88a9de41

311434666434113 has 4 divisors (see below), whose sum is σ = 313497147668928. Its totient is φ = 309372185199300.

The previous prime is 311434666434071. The next prime is 311434666434193.

311434666434113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311434666434113 - 228 = 311434397998657 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (311434666434193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1031240617181 + ... + 1031240617482.

It is an arithmetic number, because the mean of its divisors is an integer number (78374286917232).

Almost surely, 2311434666434113 is an apocalyptic number.

It is an amenable number.

311434666434113 is a deficient number, since it is larger than the sum of its proper divisors (2062481234815).

311434666434113 is a wasteful number, since it uses less digits than its factorization.

311434666434113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2062481234814.

The product of its digits is 4478976, while the sum is 50.

The spelling of 311434666434113 in words is "three hundred eleven trillion, four hundred thirty-four billion, six hundred sixty-six million, four hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 151 2062481234663 311434666434113