311440110241081 has 2 divisors, whose sum is σ = 311440110241082. Its totient is φ = 311440110241080.

The previous prime is 311440110241067. The next prime is 311440110241087. The reversal of 311440110241081 is 180142011044113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 157290727233600 + 154149383007481 = 12541560^2 + 12415691^2 .

It is a cyclic number.

It is not a de Polignac number, because 311440110241081 - 2⁵ = 311440110241049 is a prime.

It is a super-2 number, since 2×311440110241081² (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311440110241087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720055120540 + 155720055120541.

It is an arithmetic number, because the mean of its divisors is an integer number (155720055120541).

Almost surely, 2^{311440110241081} is an apocalyptic number.

It is an amenable number.

311440110241081 is a deficient number, since it is larger than the sum of its proper divisors (1).

311440110241081 is an equidigital number, since it uses as much as digits as its factorization.

311440110241081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 31.

Adding to 311440110241081 its reverse (180142011044113), we get a palindrome (491582121285194).

The spelling of 311440110241081 in words is "three hundred eleven trillion, four hundred forty billion, one hundred ten million, two hundred forty-one thousand, eighty-one".