Base | Representation |
---|---|
bin | 100011011010000001100111… |
… | …1001011000001100011100101 |
3 | 1111211201101110010211110120222 |
4 | 1012310003033023001203211 |
5 | 311310113403422404341 |
6 | 3022213343244334125 |
7 | 122412544052066210 |
oct | 10664031713014345 |
9 | 1454641403743528 |
10 | 311440144341221 |
11 | 90264029286535 |
12 | 2ab1b22a244345 |
13 | 104a18ab0b6a5c |
14 | 56c9ad7992777 |
15 | 2601415e0b44b |
hex | 11b40cf2c18e5 |
311440144341221 has 16 divisors (see below), whose sum is σ = 364245617455104. Its totient is φ = 260714423060784.
The previous prime is 311440144341217. The next prime is 311440144341233. The reversal of 311440144341221 is 122143441044113.
It is not a de Polignac number, because 311440144341221 - 22 = 311440144341217 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311440146341221) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48905465 + ... + 54905598.
It is an arithmetic number, because the mean of its divisors is an integer number (22765351090944).
Almost surely, 2311440144341221 is an apocalyptic number.
It is an amenable number.
311440144341221 is a deficient number, since it is larger than the sum of its proper divisors (52805473113883).
311440144341221 is a wasteful number, since it uses less digits than its factorization.
311440144341221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103821080.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 311440144341221 its reverse (122143441044113), we get a palindrome (433583585385334).
The spelling of 311440144341221 in words is "three hundred eleven trillion, four hundred forty billion, one hundred forty-four million, three hundred forty-one thousand, two hundred twenty-one".
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