Base | Representation |
---|---|
bin | 100011011010000001101100… |
… | …1101001110111110111000011 |
3 | 1111211201101220101202000122221 |
4 | 1012310003121221313313003 |
5 | 311310114233432401011 |
6 | 3022213412525511511 |
7 | 122412551315626333 |
oct | 10664033151676703 |
9 | 1454641811660587 |
10 | 311440320200131 |
11 | 9026410957a981 |
12 | 2ab1b279112597 |
13 | 104a190866aa95 |
14 | 56c9b1308d0c3 |
15 | 2601426597971 |
hex | 11b40d9a77dc3 |
311440320200131 has 2 divisors, whose sum is σ = 311440320200132. Its totient is φ = 311440320200130.
The previous prime is 311440320200111. The next prime is 311440320200159. The reversal of 311440320200131 is 131002023044113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 311440320200131 - 241 = 309241296944579 is a prime.
It is a super-2 number, since 2×3114403202001312 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 311440320200096 and 311440320200105.
It is not a weakly prime, because it can be changed into another prime (311440320200111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720160100065 + 155720160100066.
It is an arithmetic number, because the mean of its divisors is an integer number (155720160100066).
Almost surely, 2311440320200131 is an apocalyptic number.
311440320200131 is a deficient number, since it is larger than the sum of its proper divisors (1).
311440320200131 is an equidigital number, since it uses as much as digits as its factorization.
311440320200131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 311440320200131 its reverse (131002023044113), we get a palindrome (442442343244244).
The spelling of 311440320200131 in words is "three hundred eleven trillion, four hundred forty billion, three hundred twenty million, two hundred thousand, one hundred thirty-one".
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