31144042131 has 4 divisors (see below), whose sum is σ = 41525389512. Its totient is φ = 20762694752.

The previous prime is 31144042121. The next prime is 31144042157. The reversal of 31144042131 is 13124044113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13124044113 = 3 ⋅4374681371.

It is a cyclic number.

It is not a de Polignac number, because 31144042131 - 2⁷ = 31144042003 is a prime.

It is a super-2 number, since 2×31144042131² (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (31144042121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5190673686 + ... + 5190673691.

It is an arithmetic number, because the mean of its divisors is an integer number (10381347378).

Almost surely, 2^31144042131 is an apocalyptic number.

31144042131 is a deficient number, since it is larger than the sum of its proper divisors (10381347381).

31144042131 is a wasteful number, since it uses less digits than its factorization.

31144042131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10381347380.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 31144042131 its reverse (13124044113), we get a palindrome (44268086244).

The spelling of 31144042131 in words is "thirty-one billion, one hundred forty-four million, forty-two thousand, one hundred thirty-one".