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31144500002131 is a prime number
BaseRepresentation
bin1110001010011011001001…
…10110111111110101010011
311002021101101202100212010221
413011031210312333311103
513040232414000032011
6150123330310133511
76363054513034255
oct705154466776523
9132241352325127
1031144500002131
119a1834335230a
1235b001a051297
13144bbb5674519
1479958a92bcd5
15390217350971
hex1c5364dbfd53

31144500002131 has 2 divisors, whose sum is σ = 31144500002132. Its totient is φ = 31144500002130.

The previous prime is 31144500002117. The next prime is 31144500002153. The reversal of 31144500002131 is 13120000544113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 31144500002131 - 219 = 31144499477843 is a prime.

It is a super-2 number, since 2×311445000021312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31144500002096 and 31144500002105.

It is not a weakly prime, because it can be changed into another prime (31144500002531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15572250001065 + 15572250001066.

It is an arithmetic number, because the mean of its divisors is an integer number (15572250001066).

Almost surely, 231144500002131 is an apocalyptic number.

31144500002131 is a deficient number, since it is larger than the sum of its proper divisors (1).

31144500002131 is an equidigital number, since it uses as much as digits as its factorization.

31144500002131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 31144500002131 its reverse (13120000544113), we get a palindrome (44264500546244).

The spelling of 31144500002131 in words is "thirty-one trillion, one hundred forty-four billion, five hundred million, two thousand, one hundred thirty-one".