Base | Representation |
---|---|
bin | 101101010110010011011… |
… | …110111101011011100011 |
3 | 102000220210002111212221112 |
4 | 231112103132331123203 |
5 | 402024213332000131 |
6 | 10343341550013535 |
7 | 441101312010131 |
oct | 55262336753343 |
9 | 12026702455845 |
10 | 3116325656291 |
11 | aa1698655001 |
12 | 423b6b1a72ab |
13 | 197b397074a3 |
14 | aab8c25a751 |
15 | 560e1d5002b |
hex | 2d5937bd6e3 |
3116325656291 has 2 divisors, whose sum is σ = 3116325656292. Its totient is φ = 3116325656290.
The previous prime is 3116325656287. The next prime is 3116325656299. The reversal of 3116325656291 is 1926565236113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3116325656291 - 22 = 3116325656287 is a prime.
It is a super-3 number, since 3×31163256562913 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3116325656299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1558162828145 + 1558162828146.
It is an arithmetic number, because the mean of its divisors is an integer number (1558162828146).
Almost surely, 23116325656291 is an apocalyptic number.
3116325656291 is a deficient number, since it is larger than the sum of its proper divisors (1).
3116325656291 is an equidigital number, since it uses as much as digits as its factorization.
3116325656291 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1749600, while the sum is 50.
The spelling of 3116325656291 in words is "three trillion, one hundred sixteen billion, three hundred twenty-five million, six hundred fifty-six thousand, two hundred ninety-one".
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