Base | Representation |
---|---|
bin | 101101011000110101110… |
… | …001001001101100010001 |
3 | 102001011210211201020202021 |
4 | 231120311301021230101 |
5 | 402100302333142342 |
6 | 10344512050251441 |
7 | 441225632254243 |
oct | 55306561115421 |
9 | 12034724636667 |
10 | 3119048334097 |
11 | aa2865520153 |
12 | 4245aab86b81 |
13 | 198181801147 |
14 | aad69ab4093 |
15 | 56200db4567 |
hex | 2d635c49b11 |
3119048334097 has 2 divisors, whose sum is σ = 3119048334098. Its totient is φ = 3119048334096.
The previous prime is 3119048334043. The next prime is 3119048334113. The reversal of 3119048334097 is 7904338409113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2216394427536 + 902653906561 = 1488756^2 + 950081^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3119048334097 is a prime.
It is not a weakly prime, because it can be changed into another prime (3119048334007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1559524167048 + 1559524167049.
It is an arithmetic number, because the mean of its divisors is an integer number (1559524167049).
Almost surely, 23119048334097 is an apocalyptic number.
It is an amenable number.
3119048334097 is a deficient number, since it is larger than the sum of its proper divisors (1).
3119048334097 is an equidigital number, since it uses as much as digits as its factorization.
3119048334097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 52.
The spelling of 3119048334097 in words is "three trillion, one hundred nineteen billion, forty-eight million, three hundred thirty-four thousand, ninety-seven".
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