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31200415121 is a prime number
BaseRepresentation
bin11101000011101100…
…001000110110010001
32222112102002022100102
4131003230020312101
51002344301240441
622155553102145
72153114103251
oct350354106621
988472068312
1031200415121
1112260903747
126068b57955
132c32ca34c5
14171da45961
15c291e769b
hex743b08d91

31200415121 has 2 divisors, whose sum is σ = 31200415122. Its totient is φ = 31200415120.

The previous prime is 31200415069. The next prime is 31200415139. The reversal of 31200415121 is 12151400213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18166996225 + 13033418896 = 134785^2 + 114164^2 .

It is an emirp because it is prime and its reverse (12151400213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31200415121 - 210 = 31200414097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31200415093 and 31200415102.

It is not a weakly prime, because it can be changed into another prime (31200415151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600207560 + 15600207561.

It is an arithmetic number, because the mean of its divisors is an integer number (15600207561).

Almost surely, 231200415121 is an apocalyptic number.

It is an amenable number.

31200415121 is a deficient number, since it is larger than the sum of its proper divisors (1).

31200415121 is an equidigital number, since it uses as much as digits as its factorization.

31200415121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 31200415121 its reverse (12151400213), we get a palindrome (43351815334).

The spelling of 31200415121 in words is "thirty-one billion, two hundred million, four hundred fifteen thousand, one hundred twenty-one".