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3120122021130 = 2325616743119681
BaseRepresentation
bin101101011001110101110…
…000111100010100001010
3102001021120200001012110200
4231121311300330110022
5402110002214134010
610345210403153030
7441264350406162
oct55316560742412
912037520035420
103120122021130
11aa32665a3104
1242484a675776
131982c309b10a
14ab02c5235a2
155626529dcc0
hex2d675c3c50a

3120122021130 has 192 divisors, whose sum is σ = 8388212691456. Its totient is φ = 804266496000.

The previous prime is 3120122021113. The next prime is 3120122021147. The reversal of 3120122021130 is 311202210213.

3120122021130 is a `hidden beast` number, since 3 + 1 + 201 + 220 + 211 + 30 = 666.

3120122021130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (3120122021113) and next prime (3120122021147).

It is a super-2 number, since 2×31201220211302 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 158524890 + ... + 158544570.

It is an arithmetic number, because the mean of its divisors is an integer number (43688607768).

Almost surely, 23120122021130 is an apocalyptic number.

3120122021130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 3120122021130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4194106345728).

3120122021130 is an abundant number, since it is smaller than the sum of its proper divisors (5268090670326).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3120122021130 is a wasteful number, since it uses less digits than its factorization.

3120122021130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20253 (or 20250 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 3120122021130 its reverse (311202210213), we get a palindrome (3431324231343).

The spelling of 3120122021130 in words is "three trillion, one hundred twenty billion, one hundred twenty-two million, twenty-one thousand, one hundred thirty".