312012313431113 has 4 divisors (see below), whose sum is σ = 312012395854608. Its totient is φ = 312012231007620.

The previous prime is 312012313431011. The next prime is 312012313431223. The reversal of 312012313431113 is 311134313210213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 312012313431113 - 2³⁸ = 311737435524169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312012310431113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35245631 + ... + 43200452.

It is an arithmetic number, because the mean of its divisors is an integer number (78003098963652).

Almost surely, 2^{312012313431113} is an apocalyptic number.

It is an amenable number.

312012313431113 is a deficient number, since it is larger than the sum of its proper divisors (82423495).

312012313431113 is an equidigital number, since it uses as much as digits as its factorization.

312012313431113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82423494.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 312012313431113 its reverse (311134313210213), we get a palindrome (623146626641326).

The spelling of 312012313431113 in words is "three hundred twelve trillion, twelve billion, three hundred thirteen million, four hundred thirty-one thousand, one hundred thirteen".