Base | Representation |
---|---|
bin | 1110001100000110010010… |
… | …11001000010011101100011 |
3 | 11002110212212111200121010122 |
4 | 13012003021121002131203 |
5 | 13042203214413102433 |
6 | 150210002145350455 |
7 | 6400162113243404 |
oct | 706031131023543 |
9 | 132425774617118 |
10 | 31202021222243 |
11 | 9a3a7805aa353 |
12 | 35bb1b193842b |
13 | 14544516c1b41 |
14 | 79c2860d59ab |
15 | 39198216a198 |
hex | 1c60c9642763 |
31202021222243 has 2 divisors, whose sum is σ = 31202021222244. Its totient is φ = 31202021222242.
The previous prime is 31202021222237. The next prime is 31202021222347. The reversal of 31202021222243 is 34222212020213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31202021222243 - 210 = 31202021221219 is a prime.
It is a super-4 number, since 4×312020212222434 (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (31202021222443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601010611121 + 15601010611122.
It is an arithmetic number, because the mean of its divisors is an integer number (15601010611122).
Almost surely, 231202021222243 is an apocalyptic number.
31202021222243 is a deficient number, since it is larger than the sum of its proper divisors (1).
31202021222243 is an equidigital number, since it uses as much as digits as its factorization.
31202021222243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 31202021222243 its reverse (34222212020213), we get a palindrome (65424233242456).
The spelling of 31202021222243 in words is "thirty-one trillion, two hundred two billion, twenty-one million, two hundred twenty-two thousand, two hundred forty-three".
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