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31202213110193 is a prime number
BaseRepresentation
bin1110001100000110101001…
…10101000010000110110001
311002110220100212202111220202
413012003110311002012301
513042204113024011233
6150210033202244545
76400166633253446
oct706032465020661
9132426325674822
1031202213110193
119a3a869951634
1235bb246056755
1314544823989c8
1479c2a37a59cd
15391993e20be8
hex1c60d4d421b1

31202213110193 has 2 divisors, whose sum is σ = 31202213110194. Its totient is φ = 31202213110192.

The previous prime is 31202213110169. The next prime is 31202213110249. The reversal of 31202213110193 is 39101131220213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25742106974224 + 5460106135969 = 5073668^2 + 2336687^2 .

It is a cyclic number.

It is not a de Polignac number, because 31202213110193 - 26 = 31202213110129 is a prime.

It is a super-3 number, since 3×312022131101933 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (31202213110793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601106555096 + 15601106555097.

It is an arithmetic number, because the mean of its divisors is an integer number (15601106555097).

Almost surely, 231202213110193 is an apocalyptic number.

It is an amenable number.

31202213110193 is a deficient number, since it is larger than the sum of its proper divisors (1).

31202213110193 is an equidigital number, since it uses as much as digits as its factorization.

31202213110193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 31202213110193 in words is "thirty-one trillion, two hundred two billion, two hundred thirteen million, one hundred ten thousand, one hundred ninety-three".