Base | Representation |
---|---|
bin | 1110001100000111000010… |
… | …01111010000101001101111 |
3 | 11002110220220101112021020220 |
4 | 13012003201033100221233 |
5 | 13042210024323441421 |
6 | 150210110000542423 |
7 | 6400205042041230 |
oct | 706034117205157 |
9 | 132426811467226 |
10 | 31202421312111 |
11 | 9a3a966426835 |
12 | 35bb2a3921a13 |
13 | 14544b65652ca |
14 | 79c2c32c1087 |
15 | 3919a734a3c6 |
hex | 1c60e13d0a6f |
31202421312111 has 16 divisors (see below), whose sum is σ = 48558175417344. Its totient is φ = 17450594289504.
The previous prime is 31202421312037. The next prime is 31202421312121. The reversal of 31202421312111 is 11121312420213.
It is not a de Polignac number, because 31202421312111 - 213 = 31202421303919 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31202421312121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15806696740 + ... + 15806698713.
It is an arithmetic number, because the mean of its divisors is an integer number (3034885963584).
Almost surely, 231202421312111 is an apocalyptic number.
31202421312111 is a deficient number, since it is larger than the sum of its proper divisors (17355754105233).
31202421312111 is a wasteful number, since it uses less digits than its factorization.
31202421312111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31613395510.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 31202421312111 its reverse (11121312420213), we get a palindrome (42323733732324).
The spelling of 31202421312111 in words is "thirty-one trillion, two hundred two billion, four hundred twenty-one million, three hundred twelve thousand, one hundred eleven".
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