Base | Representation |
---|---|
bin | 100011011110011001100100… |
… | …1011010110011010010101011 |
3 | 1111220211212020201121122111111 |
4 | 1012330303021122303102223 |
5 | 311344441132332011433 |
6 | 3023353451503211151 |
7 | 122504146243265116 |
oct | 10674631132632253 |
9 | 1456755221548444 |
10 | 312041343235243 |
11 | 90475a9939a936 |
12 | 2abb78525a6ab7 |
13 | 105164ac23c1bb |
14 | 570ac4b15957d |
15 | 2611da1146dcd |
hex | 11bccc96b34ab |
312041343235243 has 2 divisors, whose sum is σ = 312041343235244. Its totient is φ = 312041343235242.
The previous prime is 312041343235151. The next prime is 312041343235331. The reversal of 312041343235243 is 342532343140213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312041343235243 - 217 = 312041343104171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312041343235196 and 312041343235205.
It is not a weakly prime, because it can be changed into another prime (312041343235043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156020671617621 + 156020671617622.
It is an arithmetic number, because the mean of its divisors is an integer number (156020671617622).
Almost surely, 2312041343235243 is an apocalyptic number.
312041343235243 is a deficient number, since it is larger than the sum of its proper divisors (1).
312041343235243 is an equidigital number, since it uses as much as digits as its factorization.
312041343235243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 312041343235243 its reverse (342532343140213), we get a palindrome (654573686375456).
The spelling of 312041343235243 in words is "three hundred twelve trillion, forty-one billion, three hundred forty-three million, two hundred thirty-five thousand, two hundred forty-three".
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