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312044231008409 is a prime number
BaseRepresentation
bin100011011110011010111010…
…1100010110010000010011001
31111220212010200222110201120012
41012330311311202302002121
5311400013041114232114
63023355050222211305
7122504310640042634
oct10674656542620231
91456763628421505
10312044231008409
1190477240478629
122abb8319723b35
131051684c5bb913
14570b0428aac1b
152611ebe91d63e
hex11bcd758b2099

312044231008409 has 2 divisors, whose sum is σ = 312044231008410. Its totient is φ = 312044231008408.

The previous prime is 312044231008397. The next prime is 312044231008417. The reversal of 312044231008409 is 904800132440213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196251996946009 + 115792234062400 = 14008997^2 + 10760680^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312044231008409 is a prime.

It is a super-2 number, since 2×3120442310084092 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (312044231008709) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156022115504204 + 156022115504205.

It is an arithmetic number, because the mean of its divisors is an integer number (156022115504205).

Almost surely, 2312044231008409 is an apocalyptic number.

It is an amenable number.

312044231008409 is a deficient number, since it is larger than the sum of its proper divisors (1).

312044231008409 is an equidigital number, since it uses as much as digits as its factorization.

312044231008409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 41.

The spelling of 312044231008409 in words is "three hundred twelve trillion, forty-four billion, two hundred thirty-one million, eight thousand, four hundred nine".