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31205414113 = 147769211177
BaseRepresentation
bin11101000011111111…
…001101010011100001
32222112202111021200021
4131003333031103201
51002402041222423
622200252153441
72153204433466
oct350377152341
988482437607
1031205414113
1112263708545
12606a768881
132c340339a3
14172058766d
15c2988395d
hex743fcd4e1

31205414113 has 4 divisors (see below), whose sum is σ = 31205773060. Its totient is φ = 31205055168.

The previous prime is 31205414099. The next prime is 31205414129. The reversal of 31205414113 is 31141450213.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 6828212689 + 24377201424 = 82633^2 + 156132^2 .

It is a cyclic number.

It is not a de Polignac number, because 31205414113 - 233 = 22615479521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31205414213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42181 + ... + 253357.

It is an arithmetic number, because the mean of its divisors is an integer number (7801443265).

Almost surely, 231205414113 is an apocalyptic number.

It is an amenable number.

31205414113 is a deficient number, since it is larger than the sum of its proper divisors (358947).

31205414113 is a wasteful number, since it uses less digits than its factorization.

31205414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 358946.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 31205414113 its reverse (31141450213), we get a palindrome (62346864326).

The spelling of 31205414113 in words is "thirty-one billion, two hundred five million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 147769 211177 31205414113