Base | Representation |
---|---|
bin | 100011011110111010100010… |
… | …0101000111101011111010011 |
3 | 1111221002121221222102221222120 |
4 | 1012331311010220331133103 |
5 | 311402121120241140311 |
6 | 3023450155541505323 |
7 | 122512233353114553 |
oct | 10675650450753723 |
9 | 1457077858387876 |
10 | 312112130021331 |
11 | 904a3013717a42 |
12 | 2b009508a12243 |
13 | 10520080691043 |
14 | 571044445b163 |
15 | 2613b4586e706 |
hex | 11bdd44a3d7d3 |
312112130021331 has 8 divisors (see below), whose sum is σ = 438052112310720. Its totient is φ = 197123450539752.
The previous prime is 312112130021327. The next prime is 312112130021347. The reversal of 312112130021331 is 133120031211213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 312112130021331 - 22 = 312112130021327 is a prime.
It is a super-2 number, since 2×3121121300213312 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (312112130021311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2737825701885 + ... + 2737825701998.
It is an arithmetic number, because the mean of its divisors is an integer number (54756514038840).
Almost surely, 2312112130021331 is an apocalyptic number.
312112130021331 is a deficient number, since it is larger than the sum of its proper divisors (125939982289389).
312112130021331 is a wasteful number, since it uses less digits than its factorization.
312112130021331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5475651403905.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 312112130021331 its reverse (133120031211213), we get a palindrome (445232161232544).
The spelling of 312112130021331 in words is "three hundred twelve trillion, one hundred twelve billion, one hundred thirty million, twenty-one thousand, three hundred thirty-one".
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