Base | Representation |
---|---|
bin | 100011011110111010100101… |
… | …0000111111111111101100001 |
3 | 1111221002122012101121012100121 |
4 | 1012331311022013333331201 |
5 | 311402121312320402001 |
6 | 3023450213030120241 |
7 | 122512235551233331 |
oct | 10675651207777541 |
9 | 1457078171535317 |
10 | 312112222044001 |
11 | 904a306065aa35 |
12 | 2b0095337b0081 |
13 | 10520096770822 |
14 | 57104527730c1 |
15 | 2613b4d99a6a1 |
hex | 11bdd4a1fff61 |
312112222044001 has 2 divisors, whose sum is σ = 312112222044002. Its totient is φ = 312112222044000.
The previous prime is 312112222043893. The next prime is 312112222044023. The reversal of 312112222044001 is 100440222211213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 213323551360000 + 98788670684001 = 14605600^2 + 9939249^2 .
It is a cyclic number.
It is not a de Polignac number, because 312112222044001 - 241 = 309913198788449 is a prime.
It is not a weakly prime, because it can be changed into another prime (312112222044401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156056111022000 + 156056111022001.
It is an arithmetic number, because the mean of its divisors is an integer number (156056111022001).
Almost surely, 2312112222044001 is an apocalyptic number.
It is an amenable number.
312112222044001 is a deficient number, since it is larger than the sum of its proper divisors (1).
312112222044001 is an equidigital number, since it uses as much as digits as its factorization.
312112222044001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 312112222044001 its reverse (100440222211213), we get a palindrome (412552444255214).
The spelling of 312112222044001 in words is "three hundred twelve trillion, one hundred twelve billion, two hundred twenty-two million, forty-four thousand, one".
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