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31211303334137 is a prime number
BaseRepresentation
bin1110001100010111100101…
…01001011111000011111001
311002111202211101121201220122
413012023302221133003321
513042331222123143022
6150214135205303025
76400641123012203
oct706136251370371
9132452741551818
1031211303334137
119a43704067403
123600b62404a75
1314552a0748b44
1479c8c6b85773
15391d26ec0742
hex1c62f2a5f0f9

31211303334137 has 2 divisors, whose sum is σ = 31211303334138. Its totient is φ = 31211303334136.

The previous prime is 31211303334121. The next prime is 31211303334149. The reversal of 31211303334137 is 73143330311213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22238995998976 + 8972307335161 = 4715824^2 + 2995381^2 .

It is a cyclic number.

It is not a de Polignac number, because 31211303334137 - 24 = 31211303334121 is a prime.

It is a super-2 number, since 2×312113033341372 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31211303334097 and 31211303334106.

It is not a weakly prime, because it can be changed into another prime (31211303334737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605651667068 + 15605651667069.

It is an arithmetic number, because the mean of its divisors is an integer number (15605651667069).

Almost surely, 231211303334137 is an apocalyptic number.

It is an amenable number.

31211303334137 is a deficient number, since it is larger than the sum of its proper divisors (1).

31211303334137 is an equidigital number, since it uses as much as digits as its factorization.

31211303334137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40824, while the sum is 35.

The spelling of 31211303334137 in words is "thirty-one trillion, two hundred eleven billion, three hundred three million, three hundred thirty-four thousand, one hundred thirty-seven".