Base | Representation |
---|---|
bin | 1110001100010111100110… |
… | …00010111010100000001011 |
3 | 11002111202211212011101221121 |
4 | 13012023303002322200023 |
5 | 13042331230330001024 |
6 | 150214140004220111 |
7 | 6400641233454463 |
oct | 706136302724013 |
9 | 132452755141847 |
10 | 31211310000139 |
11 | 9a437078aa6a5 |
12 | 3600b6469a637 |
13 | 14552a1c41019 |
14 | 79c8c79dcba3 |
15 | 391d2788a8e4 |
hex | 1c62f30ba80b |
31211310000139 has 2 divisors, whose sum is σ = 31211310000140. Its totient is φ = 31211310000138.
The previous prime is 31211310000109. The next prime is 31211310000197. The reversal of 31211310000139 is 93100001311213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31211310000139 - 27 = 31211310000011 is a prime.
It is not a weakly prime, because it can be changed into another prime (31211310000109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605655000069 + 15605655000070.
It is an arithmetic number, because the mean of its divisors is an integer number (15605655000070).
Almost surely, 231211310000139 is an apocalyptic number.
31211310000139 is a deficient number, since it is larger than the sum of its proper divisors (1).
31211310000139 is an equidigital number, since it uses as much as digits as its factorization.
31211310000139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 31211310000139 in words is "thirty-one trillion, two hundred eleven billion, three hundred ten million, one hundred thirty-nine", and thus it is an aban number.
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