312113310001 has 4 divisors (see below), whose sum is σ = 313265019904. Its totient is φ = 310961600100.

The previous prime is 312113309951. The next prime is 312113310049. The reversal of 312113310001 is 100013311213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100013311213 = 33457 ⋅2989309.

It is a cyclic number.

It is not a de Polignac number, because 312113310001 - 2¹⁵ = 312113277233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312113310401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575854545 + ... + 575855086.

It is an arithmetic number, because the mean of its divisors is an integer number (78316254976).

Almost surely, 2^312113310001 is an apocalyptic number.

It is an amenable number.

312113310001 is a deficient number, since it is larger than the sum of its proper divisors (1151709903).

312113310001 is a wasteful number, since it uses less digits than its factorization.

312113310001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1151709902.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 312113310001 its reverse (100013311213), we get a palindrome (412126621214).

The spelling of 312113310001 in words is "three hundred twelve billion, one hundred thirteen million, three hundred ten thousand, one".