Base | Representation |
---|---|
bin | 1110001100010111101011… |
… | …00000111000111010001001 |
3 | 11002111202221202002100211121 |
4 | 13012023311200320322021 |
5 | 13042331321430143421 |
6 | 150214144043555241 |
7 | 6400642245454021 |
oct | 706136540707211 |
9 | 132452852070747 |
10 | 31211351412361 |
11 | 9a4372921527a |
12 | 3600b7652bb21 |
13 | 14552aa6b05b3 |
14 | 79c8cd2dca81 |
15 | 391d2b31ad41 |
hex | 1c62f5838e89 |
31211351412361 has 2 divisors, whose sum is σ = 31211351412362. Its totient is φ = 31211351412360.
The previous prime is 31211351412317. The next prime is 31211351412383. The reversal of 31211351412361 is 16321415311213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21422493861136 + 9788857551225 = 4628444^2 + 3128715^2 .
It is a cyclic number.
It is not a de Polignac number, because 31211351412361 - 237 = 31073912458889 is a prime.
It is not a weakly prime, because it can be changed into another prime (31211051412361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605675706180 + 15605675706181.
It is an arithmetic number, because the mean of its divisors is an integer number (15605675706181).
Almost surely, 231211351412361 is an apocalyptic number.
It is an amenable number.
31211351412361 is a deficient number, since it is larger than the sum of its proper divisors (1).
31211351412361 is an equidigital number, since it uses as much as digits as its factorization.
31211351412361 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 34.
Adding to 31211351412361 its reverse (16321415311213), we get a palindrome (47532766723574).
The spelling of 31211351412361 in words is "thirty-one trillion, two hundred eleven billion, three hundred fifty-one million, four hundred twelve thousand, three hundred sixty-one".
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