Base | Representation |
---|---|
bin | 100011011110111011011101… |
… | …1010001110001010111110011 |
3 | 1111221002211002200202020212120 |
4 | 1012331312323101301113303 |
5 | 311402134204312243331 |
6 | 3023451125243125323 |
7 | 122512333602244506 |
oct | 10675667321612763 |
9 | 1457084080666776 |
10 | 312114120431091 |
11 | 904a3945204290 |
12 | 2b009983513843 |
13 | 10520309b5b1b4 |
14 | 571059293b13d |
15 | 2613c1048a796 |
hex | 11bddbb4715f3 |
312114120431091 has 32 divisors (see below), whose sum is σ = 468655908120576. Its totient is φ = 183047556192000.
The previous prime is 312114120431053. The next prime is 312114120431111. The reversal of 312114120431091 is 190134021411213.
It is not a de Polignac number, because 312114120431091 - 213 = 312114120422899 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (312114120432091) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8912245 + ... + 26526521.
It is an arithmetic number, because the mean of its divisors is an integer number (14645497128768).
Almost surely, 2312114120431091 is an apocalyptic number.
312114120431091 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
312114120431091 is a deficient number, since it is larger than the sum of its proper divisors (156541787689485).
312114120431091 is a wasteful number, since it uses less digits than its factorization.
312114120431091 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17631643.
The product of its (nonzero) digits is 5184, while the sum is 33.
The spelling of 312114120431091 in words is "three hundred twelve trillion, one hundred fourteen billion, one hundred twenty million, four hundred thirty-one thousand, ninety-one".
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