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31212103200193 = 279191117952047
BaseRepresentation
bin1110001100011001000100…
…10100101110110111000001
311002111211220010201010212101
413012030202110232313001
513042334341404401233
6150214350421230401
76401000004530206
oct706144224566701
9132454803633771
1031212103200193
119a43a84616633
123601146262401
13145539a382a76
1479c9610b7cad
15391d7231cc7d
hex1c632252edc1

31212103200193 has 4 divisors (see below), whose sum is σ = 31213221180160. Its totient is φ = 31210985220228.

The previous prime is 31212103200181. The next prime is 31212103200197. The reversal of 31212103200193 is 39100230121213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31212103200193 - 221 = 31212101103041 is a prime.

It is a super-2 number, since 2×312121032001932 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31212103200197) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 558948105 + ... + 559003942.

It is an arithmetic number, because the mean of its divisors is an integer number (7803305295040).

Almost surely, 231212103200193 is an apocalyptic number.

It is an amenable number.

31212103200193 is a deficient number, since it is larger than the sum of its proper divisors (1117979967).

31212103200193 is a wasteful number, since it uses less digits than its factorization.

31212103200193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1117979966.

The product of its (nonzero) digits is 1944, while the sum is 28.

The spelling of 31212103200193 in words is "thirty-one trillion, two hundred twelve billion, one hundred three million, two hundred thousand, one hundred ninety-three".

Divisors: 1 27919 1117952047 31212103200193