Base | Representation |
---|---|
bin | 1110001100011001010001… |
… | …10001001011110011110111 |
3 | 11002111212011200011022020120 |
4 | 13012030220301023303313 |
5 | 13042340102044301403 |
6 | 150214405242503023 |
7 | 6401002456540350 |
oct | 706145061136367 |
9 | 132455150138216 |
10 | 31212211322103 |
11 | 9a4402a655189 |
12 | 3601176504a73 |
13 | 14553b68ab326 |
14 | 79c9715c0d27 |
15 | 391d7ba78e53 |
hex | 1c6328c4bcf7 |
31212211322103 has 16 divisors (see below), whose sum is σ = 47586643050240. Its totient is φ = 17826107510016.
The previous prime is 31212211322029. The next prime is 31212211322113. The reversal of 31212211322103 is 30122311221213.
It is not a de Polignac number, because 31212211322103 - 29 = 31212211321591 is a prime.
It is a super-2 number, since 2×312122113221032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31212211322113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 393368425 + ... + 393447762.
It is an arithmetic number, because the mean of its divisors is an integer number (2974165190640).
Almost surely, 231212211322103 is an apocalyptic number.
31212211322103 is a deficient number, since it is larger than the sum of its proper divisors (16374431728137).
31212211322103 is a wasteful number, since it uses less digits than its factorization.
31212211322103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 786818086.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 31212211322103 its reverse (30122311221213), we get a palindrome (61334522543316).
The spelling of 31212211322103 in words is "thirty-one trillion, two hundred twelve billion, two hundred eleven million, three hundred twenty-two thousand, one hundred three".
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