Base | Representation |
---|---|
bin | 101101011010110111011… |
… | …000111000101111111011 |
3 | 102001101102101202022002020 |
4 | 231122313120320233323 |
5 | 402114231042330243 |
6 | 10345511533205523 |
7 | 441333546565134 |
oct | 55326730705773 |
9 | 12041371668066 |
10 | 3121223011323 |
11 | aa378102435a |
12 | 424ab73308a3 |
13 | 19843a2076c1 |
14 | ab0d483cc8b |
15 | 562cbc7d283 |
hex | 2d6b7638bfb |
3121223011323 has 8 divisors (see below), whose sum is σ = 4161692106768. Its totient is φ = 2080784628384.
The previous prime is 3121223011301. The next prime is 3121223011349. The reversal of 3121223011323 is 3231103221213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3121223011323 - 222 = 3121218817019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3121223011293 and 3121223011302.
It is not an unprimeable number, because it can be changed into a prime (3121223011393) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7439940 + ... + 7848257.
It is an arithmetic number, because the mean of its divisors is an integer number (520211513346).
Almost surely, 23121223011323 is an apocalyptic number.
3121223011323 is a deficient number, since it is larger than the sum of its proper divisors (1040469095445).
3121223011323 is a wasteful number, since it uses less digits than its factorization.
3121223011323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15356253.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 3121223011323 its reverse (3231103221213), we get a palindrome (6352326232536).
The spelling of 3121223011323 in words is "three trillion, one hundred twenty-one billion, two hundred twenty-three million, eleven thousand, three hundred twenty-three".
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