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3121304031227 is a prime number
BaseRepresentation
bin101101011010111100001…
…101111100111111111011
3102001101122001012112111102
4231122330031330333323
5402114412312444402
610345523545522015
7441335552336564
oct55327415747773
912041561175442
103121304031227
11aa3812831858
12424b1a4a330b
13198450c34085
14ab1014cd16b
15562d3e34102
hex2d6bc37cffb

3121304031227 has 2 divisors, whose sum is σ = 3121304031228. Its totient is φ = 3121304031226.

The previous prime is 3121304031173. The next prime is 3121304031233. The reversal of 3121304031227 is 7221304031213.

It is a strong prime.

It is an emirp because it is prime and its reverse (7221304031213) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3121304031227 is a prime.

It is a super-2 number, since 2×31213040312272 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3121304031227.

It is not a weakly prime, because it can be changed into another prime (3121304037227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560652015613 + 1560652015614.

It is an arithmetic number, because the mean of its divisors is an integer number (1560652015614).

Almost surely, 23121304031227 is an apocalyptic number.

3121304031227 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121304031227 is an equidigital number, since it uses as much as digits as its factorization.

3121304031227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 3121304031227 in words is "three trillion, one hundred twenty-one billion, three hundred four million, thirty-one thousand, two hundred twenty-seven".