312131031113131 has 2 divisors, whose sum is σ = 312131031113132. Its totient is φ = 312131031113130.

The previous prime is 312131031113117. The next prime is 312131031113137. The reversal of 312131031113131 is 131311130131213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312131031113131 - 2¹¹ = 312131031111083 is a prime.

It is a super-4 number, since 4×312131031113131⁴ (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 312131031113096 and 312131031113105.

It is not a weakly prime, because it can be changed into another prime (312131031113137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065515556565 + 156065515556566.

It is an arithmetic number, because the mean of its divisors is an integer number (156065515556566).

Almost surely, 2^{312131031113131} is an apocalyptic number.

312131031113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

312131031113131 is an equidigital number, since it uses as much as digits as its factorization.

312131031113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 25.

Adding to 312131031113131 its reverse (131311130131213), we get a palindrome (443442161244344).

The spelling of 312131031113131 in words is "three hundred twelve trillion, one hundred thirty-one billion, thirty-one million, one hundred thirteen thousand, one hundred thirty-one".