Base | Representation |
---|---|
bin | 100011011111000011011000… |
… | …0000000011101100101011001 |
3 | 1111221011102221210220102111021 |
4 | 1012332012300000131211121 |
5 | 311402424003432312101 |
6 | 3023503015234402441 |
7 | 122513504624435134 |
oct | 10676066000354531 |
9 | 1457142853812437 |
10 | 312131111213401 |
11 | 90500074047537 |
12 | 2b011125730421 |
13 | 10521ab6c74b3c |
14 | 57113252db21b |
15 | 26143a6e415a1 |
hex | 11be1b001d959 |
312131111213401 has 2 divisors, whose sum is σ = 312131111213402. Its totient is φ = 312131111213400.
The previous prime is 312131111213387. The next prime is 312131111213461. The reversal of 312131111213401 is 104312111131213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 309389103091600 + 2742008121801 = 17589460^2 + 1655901^2 .
It is a cyclic number.
It is not a de Polignac number, because 312131111213401 - 213 = 312131111205209 is a prime.
It is not a weakly prime, because it can be changed into another prime (312131111213461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065555606700 + 156065555606701.
It is an arithmetic number, because the mean of its divisors is an integer number (156065555606701).
Almost surely, 2312131111213401 is an apocalyptic number.
It is an amenable number.
312131111213401 is a deficient number, since it is larger than the sum of its proper divisors (1).
312131111213401 is an equidigital number, since it uses as much as digits as its factorization.
312131111213401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 312131111213401 its reverse (104312111131213), we get a palindrome (416443222344614).
The spelling of 312131111213401 in words is "three hundred twelve trillion, one hundred thirty-one billion, one hundred eleven million, two hundred thirteen thousand, four hundred one".
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