Base | Representation |
---|---|
bin | 100011011111000011011110… |
… | …1101010000110000110000011 |
3 | 1111221011110112202211201122011 |
4 | 1012332012331222012012003 |
5 | 311402424441044343133 |
6 | 3023503054055153351 |
7 | 122513513405160064 |
oct | 10676067552060603 |
9 | 1457143482751564 |
10 | 312131340231043 |
11 | 90500181349913 |
12 | 2b01118a375857 |
13 | 10521b2254bc38 |
14 | 57113478b456b |
15 | 26143bc0cd6cd |
hex | 11be1bda86183 |
312131340231043 has 2 divisors, whose sum is σ = 312131340231044. Its totient is φ = 312131340231042.
The previous prime is 312131340231019. The next prime is 312131340231077. The reversal of 312131340231043 is 340132043131213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312131340231043 - 213 = 312131340222851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312131340230996 and 312131340231014.
It is not a weakly prime, because it can be changed into another prime (312131340231743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065670115521 + 156065670115522.
It is an arithmetic number, because the mean of its divisors is an integer number (156065670115522).
Almost surely, 2312131340231043 is an apocalyptic number.
312131340231043 is a deficient number, since it is larger than the sum of its proper divisors (1).
312131340231043 is an equidigital number, since it uses as much as digits as its factorization.
312131340231043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 312131340231043 its reverse (340132043131213), we get a palindrome (652263383362256).
The spelling of 312131340231043 in words is "three hundred twelve trillion, one hundred thirty-one billion, three hundred forty million, two hundred thirty-one thousand, forty-three".
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