Base | Representation |
---|---|
bin | 100011011111000011110110… |
… | …1011101000011110100110011 |
3 | 1111221011112121122201220211011 |
4 | 1012332013231131003310303 |
5 | 311402433111340321433 |
6 | 3023503305422331351 |
7 | 122513542313132344 |
oct | 10676075535036463 |
9 | 1457145548656734 |
10 | 312132142120243 |
11 | 90500552a60065 |
12 | 2b011372a29b57 |
13 | 10521c1c7139a3 |
14 | 57113c21b20cb |
15 | 26144176ca3cd |
hex | 11be1ed743d33 |
312132142120243 has 4 divisors (see below), whose sum is σ = 312311425374208. Its totient is φ = 311952858866280.
The previous prime is 312132142120241. The next prime is 312132142120259. The reversal of 312132142120243 is 342021241231213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312132142120243 - 21 = 312132142120241 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (312132142120241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89641624371 + ... + 89641627852.
It is an arithmetic number, because the mean of its divisors is an integer number (78077856343552).
Almost surely, 2312132142120243 is an apocalyptic number.
312132142120243 is a deficient number, since it is larger than the sum of its proper divisors (179283253965).
312132142120243 is a wasteful number, since it uses less digits than its factorization.
312132142120243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179283253964.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 312132142120243 its reverse (342021241231213), we get a palindrome (654153383351456).
The spelling of 312132142120243 in words is "three hundred twelve trillion, one hundred thirty-two billion, one hundred forty-two million, one hundred twenty thousand, two hundred forty-three".
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