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312132311269547 is a prime number
BaseRepresentation
bin100011011111000011111011…
…1100010010100000010101011
31111221011120001110000121001012
41012332013313202110002223
5311402433433141111142
63023503334304014135
7122513546435646116
oct10676076742240253
91457146043017035
10312132311269547
119050062a49147a
122b0113bb60134b
1310521c48788a32
1457113da84357d
15261442748d882
hex11be1f78940ab

312132311269547 has 2 divisors, whose sum is σ = 312132311269548. Its totient is φ = 312132311269546.

The previous prime is 312132311269523. The next prime is 312132311269553. The reversal of 312132311269547 is 745962113231213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312132311269547 - 28 = 312132311269291 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312132311269495 and 312132311269504.

It is not a weakly prime, because it can be changed into another prime (312132311269507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066155634773 + 156066155634774.

It is an arithmetic number, because the mean of its divisors is an integer number (156066155634774).

Almost surely, 2312132311269547 is an apocalyptic number.

312132311269547 is a deficient number, since it is larger than the sum of its proper divisors (1).

312132311269547 is an equidigital number, since it uses as much as digits as its factorization.

312132311269547 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1632960, while the sum is 50.

The spelling of 312132311269547 in words is "three hundred twelve trillion, one hundred thirty-two billion, three hundred eleven million, two hundred sixty-nine thousand, five hundred forty-seven".