Base | Representation |
---|---|
bin | 100011011111000100010000… |
… | …1010100100101010011010011 |
3 | 1111221011121212022011022021121 |
4 | 1012332020201110211103103 |
5 | 311402441402123011144 |
6 | 3023503532025503111 |
7 | 122513603010505342 |
oct | 10676104124452323 |
9 | 1457147768138247 |
10 | 312133012313299 |
11 | 9050095a183a81 |
12 | 2b011576341a97 |
13 | 1052202aaa2218 |
14 | 57114659adb59 |
15 | 2614468cba384 |
hex | 11be2215254d3 |
312133012313299 has 2 divisors, whose sum is σ = 312133012313300. Its totient is φ = 312133012313298.
The previous prime is 312133012313261. The next prime is 312133012313323. The reversal of 312133012313299 is 992313210331213.
It is a strong prime.
It is an emirp because it is prime and its reverse (992313210331213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312133012313299 - 217 = 312133012182227 is a prime.
It is not a weakly prime, because it can be changed into another prime (312133012313209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066506156649 + 156066506156650.
It is an arithmetic number, because the mean of its divisors is an integer number (156066506156650).
Almost surely, 2312133012313299 is an apocalyptic number.
312133012313299 is a deficient number, since it is larger than the sum of its proper divisors (1).
312133012313299 is an equidigital number, since it uses as much as digits as its factorization.
312133012313299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 157464, while the sum is 43.
The spelling of 312133012313299 in words is "three hundred twelve trillion, one hundred thirty-three billion, twelve million, three hundred thirteen thousand, two hundred ninety-nine".
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