Base | Representation |
---|---|
bin | 100011011111000100011001… |
… | …0100011011100111110001011 |
3 | 1111221011122121110011122121202 |
4 | 1012332020302203130332023 |
5 | 311402443000131032021 |
6 | 3023504020434254415 |
7 | 122513613121062614 |
oct | 10676106243347613 |
9 | 1457148543148552 |
10 | 312133301424011 |
11 | 90500a983a0151 |
12 | 2b01163712740b |
13 | 10522075959752 |
14 | 571149214ac0b |
15 | 2614484377a0b |
hex | 11be2328dcf8b |
312133301424011 has 2 divisors, whose sum is σ = 312133301424012. Its totient is φ = 312133301424010.
The previous prime is 312133301423989. The next prime is 312133301424047. The reversal of 312133301424011 is 110424103331213.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312133301424011 is a prime.
It is not a weakly prime, because it can be changed into another prime (312133301420011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156066650712005 + 156066650712006.
It is an arithmetic number, because the mean of its divisors is an integer number (156066650712006).
Almost surely, 2312133301424011 is an apocalyptic number.
312133301424011 is a deficient number, since it is larger than the sum of its proper divisors (1).
312133301424011 is an equidigital number, since it uses as much as digits as its factorization.
312133301424011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 312133301424011 its reverse (110424103331213), we get a palindrome (422557404755224).
The spelling of 312133301424011 in words is "three hundred twelve trillion, one hundred thirty-three billion, three hundred one million, four hundred twenty-four thousand, eleven".
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