Base | Representation |
---|---|
bin | 11101000100100000… |
… | …000000001101000001 |
3 | 2222120100200001122221 |
4 | 131010200000031001 |
5 | 1002411241324301 |
6 | 22201200331041 |
7 | 2153340501052 |
oct | 350440001501 |
9 | 88510601587 |
10 | 31214011201 |
11 | 1226854a67a |
12 | 6071613a81 |
13 | 2c35a53b19 |
14 | 1721784729 |
15 | c2a4d0da1 |
hex | 744800341 |
31214011201 has 2 divisors, whose sum is σ = 31214011202. Its totient is φ = 31214011200.
The previous prime is 31214011193. The next prime is 31214011207. The reversal of 31214011201 is 10211041213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29551329025 + 1662682176 = 171905^2 + 40776^2 .
It is an emirp because it is prime and its reverse (10211041213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31214011201 - 23 = 31214011193 is a prime.
It is not a weakly prime, because it can be changed into another prime (31214011207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607005600 + 15607005601.
It is an arithmetic number, because the mean of its divisors is an integer number (15607005601).
Almost surely, 231214011201 is an apocalyptic number.
It is an amenable number.
31214011201 is a deficient number, since it is larger than the sum of its proper divisors (1).
31214011201 is an equidigital number, since it uses as much as digits as its factorization.
31214011201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 31214011201 its reverse (10211041213), we get a palindrome (41425052414).
The spelling of 31214011201 in words is "thirty-one billion, two hundred fourteen million, eleven thousand, two hundred one".
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