Base | Representation |
---|---|
bin | 1110001100011100110100… |
… | …00111101011011111011011 |
3 | 11002112001002012120210212022 |
4 | 13012032122013223133123 |
5 | 13042403000414410233 |
6 | 150215322055205055 |
7 | 6401100551112350 |
oct | 706163207533733 |
9 | 132461065523768 |
10 | 31214113044443 |
11 | 9a4491607733a |
12 | 360160737678b |
13 | 145562a895b14 |
14 | 79cab1db6627 |
15 | 391e3d9c7398 |
hex | 1c639a1eb7db |
31214113044443 has 4 divisors (see below), whose sum is σ = 35673272050800. Its totient is φ = 26754954038088.
The previous prime is 31214113044403. The next prime is 31214113044451. The reversal of 31214113044443 is 34444031141213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31214113044443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31214113044403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2229579503168 + ... + 2229579503181.
It is an arithmetic number, because the mean of its divisors is an integer number (8918318012700).
Almost surely, 231214113044443 is an apocalyptic number.
31214113044443 is a deficient number, since it is larger than the sum of its proper divisors (4459159006357).
31214113044443 is an equidigital number, since it uses as much as digits as its factorization.
31214113044443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4459159006356.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 31214113044443 its reverse (34444031141213), we get a palindrome (65658144185656).
The spelling of 31214113044443 in words is "thirty-one trillion, two hundred fourteen billion, one hundred thirteen million, forty-four thousand, four hundred forty-three".
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