Base | Representation |
---|---|
bin | 100011011111001000000100… |
… | …1100010011011001110111001 |
3 | 1111221012102000010210122201101 |
4 | 1012332100021202123032321 |
5 | 311403110141011122411 |
6 | 3023511404505251401 |
7 | 122514313000214062 |
oct | 10676201142331671 |
9 | 1457172003718641 |
10 | 312141203223481 |
11 | 90504382796035 |
12 | 2b013081493b61 |
13 | 10522a34a39138 |
14 | 5711a01771569 |
15 | 2614797e268c1 |
hex | 11be40989b3b9 |
312141203223481 has 2 divisors, whose sum is σ = 312141203223482. Its totient is φ = 312141203223480.
The previous prime is 312141203223407. The next prime is 312141203223517. The reversal of 312141203223481 is 184322302141213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 274258606170025 + 37882597053456 = 16560755^2 + 6154884^2 .
It is an emirp because it is prime and its reverse (184322302141213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312141203223481 - 217 = 312141203092409 is a prime.
It is a super-2 number, since 2×3121412032234812 (a number of 30 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 312141203223481.
It is not a weakly prime, because it can be changed into another prime (312141203223181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070601611740 + 156070601611741.
It is an arithmetic number, because the mean of its divisors is an integer number (156070601611741).
Almost surely, 2312141203223481 is an apocalyptic number.
It is an amenable number.
312141203223481 is a deficient number, since it is larger than the sum of its proper divisors (1).
312141203223481 is an equidigital number, since it uses as much as digits as its factorization.
312141203223481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 37.
Adding to 312141203223481 its reverse (184322302141213), we get a palindrome (496463505364694).
The spelling of 312141203223481 in words is "three hundred twelve trillion, one hundred forty-one billion, two hundred three million, two hundred twenty-three thousand, four hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •