Base | Representation |
---|---|
bin | 1110001100011101011011… |
… | …10110101101101010100011 |
3 | 11002112001221021121021020212 |
4 | 13012032231312231222203 |
5 | 13042404140200004334 |
6 | 150215415003524335 |
7 | 6401112011306153 |
oct | 706165566555243 |
9 | 132461837537225 |
10 | 31214444141219 |
11 | 9a44a75a60239 |
12 | 360169a2296ab |
13 | 1455681360b81 |
14 | 79cb03d62763 |
15 | 391e5cac9ece |
hex | 1c63addadaa3 |
31214444141219 has 2 divisors, whose sum is σ = 31214444141220. Its totient is φ = 31214444141218.
The previous prime is 31214444141201. The next prime is 31214444141249. The reversal of 31214444141219 is 91214144441213.
It is a weak prime.
It is an emirp because it is prime and its reverse (91214144441213) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31214444141219 is a prime.
It is a super-2 number, since 2×312144441412192 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31214444141249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607222070609 + 15607222070610.
It is an arithmetic number, because the mean of its divisors is an integer number (15607222070610).
Almost surely, 231214444141219 is an apocalyptic number.
31214444141219 is a deficient number, since it is larger than the sum of its proper divisors (1).
31214444141219 is an equidigital number, since it uses as much as digits as its factorization.
31214444141219 is an evil number, because the sum of its binary digits is even.
The product of its digits is 110592, while the sum is 41.
The spelling of 31214444141219 in words is "thirty-one trillion, two hundred fourteen billion, four hundred forty-four million, one hundred forty-one thousand, two hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.982 sec. • engine limits •