Base | Representation |
---|---|
bin | 101101011011100110010… |
… | …100001100110101010011 |
3 | 102001110110021012022121021 |
4 | 231123212110030311103 |
5 | 402122334114441034 |
6 | 10350122015540311 |
7 | 441362216540344 |
oct | 55334624146523 |
9 | 12043407168537 |
10 | 3122010312019 |
11 | aa4045480a95 |
12 | 425096b2a697 |
13 | 1985343621c1 |
14 | ab16b2200cb |
15 | 56325e476b4 |
hex | 2d6e650cd53 |
3122010312019 has 2 divisors, whose sum is σ = 3122010312020. Its totient is φ = 3122010312018.
The previous prime is 3122010311999. The next prime is 3122010312037. The reversal of 3122010312019 is 9102130102213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3122010312019 - 239 = 2572254498131 is a prime.
It is a super-2 number, since 2×31220103120192 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3122010311984 and 3122010312002.
It is not a weakly prime, because it can be changed into another prime (3122010312919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561005156009 + 1561005156010.
It is an arithmetic number, because the mean of its divisors is an integer number (1561005156010).
Almost surely, 23122010312019 is an apocalyptic number.
3122010312019 is a deficient number, since it is larger than the sum of its proper divisors (1).
3122010312019 is an equidigital number, since it uses as much as digits as its factorization.
3122010312019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 3122010312019 in words is "three trillion, one hundred twenty-two billion, ten million, three hundred twelve thousand, nineteen".
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