Base | Representation |
---|---|
bin | 100011011111100100000001… |
… | …0111101011010101111100001 |
3 | 1111221102010220222110210001211 |
4 | 1012333020002331122233201 |
5 | 311410101100413312433 |
6 | 3023555132300430121 |
7 | 122521536221623642 |
oct | 10677100275325741 |
9 | 1457363828423054 |
10 | 312201222400993 |
11 | 90527881a81482 |
12 | 2b022831848341 |
13 | 105285ab44c263 |
14 | 57148969b76c9 |
15 | 261610c1b68cd |
hex | 11bf202f5abe1 |
312201222400993 has 2 divisors, whose sum is σ = 312201222400994. Its totient is φ = 312201222400992.
The previous prime is 312201222400961. The next prime is 312201222401023. The reversal of 312201222400993 is 399004222102213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 283297136833489 + 28904085567504 = 16831433^2 + 5376252^2 .
It is a cyclic number.
It is not a de Polignac number, because 312201222400993 - 25 = 312201222400961 is a prime.
It is not a weakly prime, because it can be changed into another prime (312201222406993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156100611200496 + 156100611200497.
It is an arithmetic number, because the mean of its divisors is an integer number (156100611200497).
Almost surely, 2312201222400993 is an apocalyptic number.
It is an amenable number.
312201222400993 is a deficient number, since it is larger than the sum of its proper divisors (1).
312201222400993 is an equidigital number, since it uses as much as digits as its factorization.
312201222400993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 40.
The spelling of 312201222400993 in words is "three hundred twelve trillion, two hundred one billion, two hundred twenty-two million, four hundred thousand, nine hundred ninety-three".
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