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3122040402241 is a prime number
BaseRepresentation
bin101101011011101000000…
…110111111000101000001
3102001110112100211001121221
4231123220012333011001
5402122414320332431
610350125012515041
7441363033363055
oct55335006770501
912043470731557
103122040402241
11aa4060463242
124250a501ba81
1319853a669277
14ab171213c65
15563288dd111
hex2d6e81bf141

3122040402241 has 2 divisors, whose sum is σ = 3122040402242. Its totient is φ = 3122040402240.

The previous prime is 3122040402109. The next prime is 3122040402323. The reversal of 3122040402241 is 1422040402213.

3122040402241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1641206961216 + 1480833441025 = 1281096^2 + 1216895^2 .

It is an emirp because it is prime and its reverse (1422040402213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3122040402241 - 225 = 3122006847809 is a prime.

It is not a weakly prime, because it can be changed into another prime (3122040406241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561020201120 + 1561020201121.

It is an arithmetic number, because the mean of its divisors is an integer number (1561020201121).

Almost surely, 23122040402241 is an apocalyptic number.

It is an amenable number.

3122040402241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3122040402241 is an equidigital number, since it uses as much as digits as its factorization.

3122040402241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 3122040402241 its reverse (1422040402213), we get a palindrome (4544080804454).

The spelling of 3122040402241 in words is "three trillion, one hundred twenty-two billion, forty million, four hundred two thousand, two hundred forty-one".